Consider a sequence of seven
consecutive integers. The average of first five integers is n. the average of
all seven integers is:
(1)n (2) n+1
(3) K*n, where K is a function
of n (4) n+(2/7)
Solution follows here:
Solution:
Given that it is a sequence of 7
consecutive integers. As the average of first five integers is n, sum of first
five integers is 5n.
=> t1+t2+t3+t4+t5
= 5n ------(1)
As they are consecutive integers, the
middle number of the first five numbers is nothing but average of the five
numbers ie., ‘n’.
=> t3 = n => t4
= n+1 => t5 = n+2 => t6 = n+3 => t7 =
n+4
=> t6+t7 = n+3+n+4
= 2n+7 ------(2)
Adding (1) and (2),
t1+t2+t3+t4+t5+t6+t7=
5n+2n+7 = 7n+7
=> Average of all 7 numbers = (t1+t2+t3+t4+t5+t6+t7)/7
= n+1
Answer (2)
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