Saturday 22 October 2011

Geometry -1 (IIFT-2008)

If D is the mid point of side BC of a triangle ABC and AD is the perpendicular to AC then:
(A)  3AC2 = BC2-AB2
(B)  3BC2 = AC2-3AB2
(C)  BC2+ AC2 = 5AB2
(D) None of the above
To enter your answer, click on "comments" below:

3 comments:

  1. D

    see consider a triangle with base 8cm(BC) and altitude 3(let be AD).


    since D bisects and form right angle,we have 2 RIGHT ANGLED TRIANGLE with height AD(=3cm)
    bases BD(=4cm) and DC(=4cm).

    then using pythogorus theorem,we get AB=5cm and AD=5cm
    subtituting the values in the above four options ,i am getting none of them satisfied

    SO answer option is D)NONE of the above

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    Replies
    1. In the question, it is given that AD is perpendicular to AC but not to BC...

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